What are the solutions to the equation 3x^2+6x-6=0 ?

The solutions to the equation 3x^2+6x-6=0 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of 3x^2+6x-6=0

The zeros of 3x^2+6x-6=0 are x=-1+sqrt(3),x=-1-sqrt(3)

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3 x^{2} + 6 x - 6 = 0

x = - 1 + 3, x = - 1 - 3

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

3 x^{2} + 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 6) = 63

x_{1, 2} = \frac{- 6 \pm 6 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 3}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 3}{2 \cdot 3}

x = \frac{- 6 + 6 3}{2 \cdot 3} : - 1 + 3

x = \frac{- 6 - 6 3}{2 \cdot 3} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

w^{5} x^{5} y^{5} - w x^{4} y^{5}

2 x^{2} + 9 x + 10 = 0

16378 = \frac{x ^{2}}{398600}

2 x^{2} - 9 x - 5

x^{2} - 81 x = 0

What are the solutions to the equation 3x^2+6x-6=0 ?
The solutions to the equation 3x^2+6x-6=0 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of 3x^2+6x-6=0
The zeros of 3x^2+6x-6=0 are x=-1+sqrt(3),x=-1-sqrt(3)