What are the solutions to the equation 10x^2+11x-6=0 ?

The solutions to the equation 10x^2+11x-6=0 are x= 2/5 ,x=-3/2

Find the zeros of 10x^2+11x-6=0

The zeros of 10x^2+11x-6=0 are x= 2/5 ,x=-3/2

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10 x^{2} + 11 x - 6 = 0

x = \frac{2}{5}, x = - \frac{3}{2}

Decimal Notation

x = 0.4, x = - 1.5

Solution steps

10 x^{2} + 11 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 10 ( - 6 )}{2 \cdot 10}

1 1^{2} - 4 \cdot 10 (- 6) = 19

x_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 11 + 19}{2 \cdot 10}, x_{2} = \frac{- 11 - 19}{2 \cdot 10}

x = \frac{- 11 + 19}{2 \cdot 10} : \frac{2}{5}

x = \frac{- 11 - 19}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{3}{2}

10 v^{2} + 23 v + 12

1 + p = 2 p - 1

v^{2} + 8 v + 7

(x + 8) (x - 98) < 0

\frac{2 ^{2}}{2 ^{4}}

What are the solutions to the equation 10x^2+11x-6=0 ?
The solutions to the equation 10x^2+11x-6=0 are x= 2/5 ,x=-3/2
Find the zeros of 10x^2+11x-6=0
The zeros of 10x^2+11x-6=0 are x= 2/5 ,x=-3/2