What are the solutions to the equation u^2+14u+49=0 ?

The solutions to the equation u^2+14u+49=0 are u=-7

Find the zeros of u^2+14u+49=0

The zeros of u^2+14u+49=0 are u=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} + 14 u + 49 = 0

u = - 7

Solution steps

u^{2} + 14 u + 49 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

u_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

u = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

u = - 7

The solution to the quadratic equation is:

u = - 7

- 10 + 2 (- 9 d + 8) < 6 d + 10 - 2

- x \leq - 1

6 x^{2} - 54

[\frac{a x}{- x ^{2}}]^{5}

ln (3 x + 3 y)

What are the solutions to the equation u^2+14u+49=0 ?
The solutions to the equation u^2+14u+49=0 are u=-7
Find the zeros of u^2+14u+49=0
The zeros of u^2+14u+49=0 are u=-7