What is factor x^4-2x^3-8x+16 ?

The solution to factor x^4-2x^3-8x+16 is (x-2)^2(x^2+2x+4)

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factor x^4-2x^3-8x+16

factor

x^{4} - 2 x^{3} - 8 x + 16

(x - 2)^{2} (x^{2} + 2 x + 4)

Solution steps

x^{4} - 2 x^{3} - 8 x + 16

= (x^{4} - 2 x^{3}) + (- 8 x + 16)

Factor out

x^{3}

from

x^{4} - 2 x^{3} : x^{3} (x - 2)

Factor out

- 8

from

- 8 x + 16 : - 8 (x - 2)

= x^{3} (x - 2) - 8 (x - 2)

Factor out common term

x - 2

= (x - 2) (x^{3} - 8)

Factor

x^{3} - 8 : (x - 2) (x^{2} + 2 x + 2^{2})

= (x - 2) (x - 2) (x^{2} + 2 x + 2^{2})

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x - 2)^{2} (x^{2} + 2 x + 2^{2})

2^{2} = 4

= (x - 2)^{2} (x^{2} + 2 x + 4)

81 x^{6} - (y + 1)^{2}

\frac{5 ( x - 2 )}{6} - x = 1 - \frac{x}{9}

20 - 23 [(2 - 8) + (6 + 2) (2 - 7)] - 4 - 3 + 7 [2 - 5 (2 - 6)]

\frac{w}{2} - 1 \geq 1

\frac{w - 2}{3} > \frac{1}{2}

What is factor x^4-2x^3-8x+16 ?
The solution to factor x^4-2x^3-8x+16 is (x-2)^2(x^2+2x+4)