What are the solutions to the equation 3q^2-20q+30=0 ?

The solutions to the equation 3q^2-20q+30=0 are q=(10+sqrt(10))/3 ,q=(10-sqrt(10))/3

Find the zeros of 3q^2-20q+30=0

The zeros of 3q^2-20q+30=0 are q=(10+sqrt(10))/3 ,q=(10-sqrt(10))/3

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3 q^{2} - 20 q + 30 = 0

q = \frac{10 + 10}{3}, q = \frac{10 - 10}{3}

Decimal Notation

q = 4.38742 \dots, q = 2.27924 \dots

Solution steps

3 q^{2} - 20 q + 30 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 3 \cdot 30}{2 \cdot 3}

(- 20)^{2} - 4 \cdot 3 \cdot 30 = 210

q_{1, 2} = \frac{- ( - 20 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 20 ) + 2 10}{2 \cdot 3}, q_{2} = \frac{- ( - 20 ) - 2 10}{2 \cdot 3}

q = \frac{- ( - 20 ) + 2 10}{2 \cdot 3} : \frac{10 + 10}{3}

q = \frac{- ( - 20 ) - 2 10}{2 \cdot 3} : \frac{10 - 10}{3}

The solutions to the quadratic equation are:

q = \frac{10 + 10}{3}, q = \frac{10 - 10}{3}

625 - 25 ∣ 3 - 1990 ∣ = 550

- \frac{2}{5} + 5

\frac{x + \frac{y}{x}}{y + \frac{x}{y}}

250 + 20 h = 300

(8^{\frac{5}{3}})^{\frac{1}{5}}

What are the solutions to the equation 3q^2-20q+30=0 ?
The solutions to the equation 3q^2-20q+30=0 are q=(10+sqrt(10))/3 ,q=(10-sqrt(10))/3
Find the zeros of 3q^2-20q+30=0
The zeros of 3q^2-20q+30=0 are q=(10+sqrt(10))/3 ,q=(10-sqrt(10))/3