What are the solutions to the equation x^2+7x-8=0 ?

The solutions to the equation x^2+7x-8=0 are x=1,x=-8

Find the zeros of x^2+7x-8=0

The zeros of x^2+7x-8=0 are x=1,x=-8

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x^{2} + 7 x - 8 = 0

x = 1, x = - 8

Solution steps

x^{2} + 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 8) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 1}, x_{2} = \frac{- 7 - 9}{2 \cdot 1}

x = \frac{- 7 + 9}{2 \cdot 1} : 1

x = \frac{- 7 - 9}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 1, x = - 8

8 x + 9 \leq 16 x - 11

∣ x + 3 ∣ \leq 8

lo g_{3} (33) = x

\frac{3 11 x ^{3} y}{- 2 12 x ^{4} y}

What are the solutions to the equation x^2+7x-8=0 ?
The solutions to the equation x^2+7x-8=0 are x=1,x=-8
Find the zeros of x^2+7x-8=0
The zeros of x^2+7x-8=0 are x=1,x=-8