What is 2+sqrt(5x-1)>5 ?

The solution to 2+sqrt(5x-1)>5 is x>2

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2+sqrt(5x-1)>5

2 + 5 x - 1 > 5

x > 2

Interval Notation

(2, \infty)

Solution steps

2 + 5 x - 1 > 5

Move

2

to the right side

5 x - 1 > 3

Square both sides

(5 x - 1)^{2} > 3^{2}

Simplify

5 x - 1 > 9

5 x - 1 > 9 : x > 2

x > 2

Find singularity points

Find non-negative values for radicals:

x \geq \frac{1}{5}

Combine the intervals

x > 2 and x \geq \frac{1}{5}

Merge Overlapping Intervals

x > 2

e^{i \cdot \frac{π}{4}}

- 5 > x

- 2 x^{2} - x + 3 = 0

n^{2} - 19 n + 88

x^{2} - 8 x = - 12