What are the solutions to the equation 3(x+4)^2=36 ?

The solutions to the equation 3(x+4)^2=36 are x=2sqrt(3)-4,x=-2sqrt(3)-4

Find the zeros of 3(x+4)^2=36

The zeros of 3(x+4)^2=36 are x=2sqrt(3)-4,x=-2sqrt(3)-4

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3 (x + 4)^{2} = 36

x = 23 - 4, x = - 23 - 4

Decimal Notation

x = - 0.53589 \dots, x = - 7.46410 \dots

Solution steps

3 (x + 4)^{2} = 36

Divide both sides by

3

(x + 4)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 12 : x = 23 - 4

Solve

x + 4 = - 12 : x = - 23 - 4

The solutions to the quadratic equation are:

x = 23 - 4, x = - 23 - 4

y^{2} - 3 y - 40

y^{2} - 7 y + 12

3 x < 8

9 (x + 2) = x - 6

5 x + 1 \leq 2.5

What are the solutions to the equation 3(x+4)^2=36 ?
The solutions to the equation 3(x+4)^2=36 are x=2sqrt(3)-4,x=-2sqrt(3)-4
Find the zeros of 3(x+4)^2=36
The zeros of 3(x+4)^2=36 are x=2sqrt(3)-4,x=-2sqrt(3)-4