What are the solutions to the equation v^2-v-20=0 ?

The solutions to the equation v^2-v-20=0 are v=5,v=-4

Find the zeros of v^2-v-20=0

The zeros of v^2-v-20=0 are v=5,v=-4

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v^{2} - v - 20 = 0

v = 5, v = - 4

Solution steps

v^{2} - v - 20 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

v_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, v_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

v = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

v = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

v = 5, v = - 4

(1 + \frac{0.05}{2})^{2} - 1

5 (2 - y) - y = 2 (y + 1)

\frac{32}{2 π}

1 \geq \frac{s + 4}{12}

23 \cdot 2

What are the solutions to the equation v^2-v-20=0 ?
The solutions to the equation v^2-v-20=0 are v=5,v=-4
Find the zeros of v^2-v-20=0
The zeros of v^2-v-20=0 are v=5,v=-4