What are the solutions to the equation 3x^2+16=2 ?

The solutions to the equation 3x^2+16=2 are x=sqrt(14/3)i,x=-sqrt(14/3)i

Find the zeros of 3x^2+16=2

The zeros of 3x^2+16=2 are x=sqrt(14/3)i,x=-sqrt(14/3)i

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3 x^{2} + 16 = 2

x = \frac{14}{3} i, x = - \frac{14}{3} i

Solution steps

3 x^{2} + 16 = 2

Move

16

to the right side

3 x^{2} = - 14

Divide both sides by

3

x^{2} = - \frac{14}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{14}{3}, x = - - \frac{14}{3}

- \frac{14}{3} = \frac{14}{3} i

- - \frac{14}{3} = - \frac{14}{3} i

x = \frac{14}{3} i, x = - \frac{14}{3} i

4 x^{4} y + 10 x^{3} y - 36 x^{2} y - 90 x y

x^{2} - 5 x = 2

10 - 10 ∣ - 8 k + 4 ∣ = 10

\frac{10 ( x + y ) ^{3}}{4 ( x + y ) ^{- 2}}

(7 y)^{2}

What are the solutions to the equation 3x^2+16=2 ?
The solutions to the equation 3x^2+16=2 are x=sqrt(14/3)i,x=-sqrt(14/3)i
Find the zeros of 3x^2+16=2
The zeros of 3x^2+16=2 are x=sqrt(14/3)i,x=-sqrt(14/3)i