What are the solutions to the equation (7x-4)^2=49 ?

The solutions to the equation (7x-4)^2=49 are x= 11/7 ,x=-3/7

Find the zeros of (7x-4)^2=49

The zeros of (7x-4)^2=49 are x= 11/7 ,x=-3/7

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(7 x - 4)^{2} = 49

x = \frac{11}{7}, x = - \frac{3}{7}

Decimal Notation

x = 1.57142 \dots, x = - 0.42857 \dots

Solution steps

(7 x - 4)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x - 4 = 49 : x = \frac{11}{7}

Solve

7 x - 4 = - 49 : x = - \frac{3}{7}

The solutions to the quadratic equation are:

x = \frac{11}{7}, x = - \frac{3}{7}

(- 8)^{3}

\frac{35}{36}

15 x^{2} = 0

2 u^{2} + 7 u + 7 = (u + 1)^{2}

x^{2} - 5 x - x y + 5 y

What are the solutions to the equation (7x-4)^2=49 ?
The solutions to the equation (7x-4)^2=49 are x= 11/7 ,x=-3/7
Find the zeros of (7x-4)^2=49
The zeros of (7x-4)^2=49 are x= 11/7 ,x=-3/7