What are the solutions to the equation 6x^2-4x-1=0 ?

The solutions to the equation 6x^2-4x-1=0 are x=(2+sqrt(10))/6 ,x=(2-sqrt(10))/6

Find the zeros of 6x^2-4x-1=0

The zeros of 6x^2-4x-1=0 are x=(2+sqrt(10))/6 ,x=(2-sqrt(10))/6

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6 x^{2} - 4 x - 1 = 0

x = \frac{2 + 10}{6}, x = \frac{2 - 10}{6}

Decimal Notation

x = 0.86037 \dots, x = - 0.19371 \dots

Solution steps

6 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 4)^{2} - 4 \cdot 6 (- 1) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 6}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 6} : \frac{2 + 10}{6}

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 6} : \frac{2 - 10}{6}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{6}, x = \frac{2 - 10}{6}

- 1 = \frac{1}{2} (3) + b

18 m^{3} + 39 m^{2} n - 15 m n^{2}

x^{2} - 5 x = 6

3 d - 7 d + 2.8 < 5.8 - 27

∣ 8 x - 7 ∣ - 9 > - 11

What are the solutions to the equation 6x^2-4x-1=0 ?
The solutions to the equation 6x^2-4x-1=0 are x=(2+sqrt(10))/6 ,x=(2-sqrt(10))/6
Find the zeros of 6x^2-4x-1=0
The zeros of 6x^2-4x-1=0 are x=(2+sqrt(10))/6 ,x=(2-sqrt(10))/6