What are the solutions to the equation x^2-6x+7=2 ?

The solutions to the equation x^2-6x+7=2 are x=5,x=1

Find the zeros of x^2-6x+7=2

The zeros of x^2-6x+7=2 are x=5,x=1

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x^{2} - 6 x + 7 = 2

x = 5, x = 1

Solution steps

x^{2} - 6 x + 7 = 2

Move

2

to the left side

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

7 p^{2} + 8 p - 1 = 5 p^{2}

100 0^{3}

49 + 49

- 6 x = 3 (5 x + 8) - 3

\frac{3}{5} + \frac{1}{2}

What are the solutions to the equation x^2-6x+7=2 ?
The solutions to the equation x^2-6x+7=2 are x=5,x=1
Find the zeros of x^2-6x+7=2
The zeros of x^2-6x+7=2 are x=5,x=1