What are the solutions to the equation 4x^2+6x=7 ?

The solutions to the equation 4x^2+6x=7 are x=(-3+sqrt(37))/4 ,x=-(3+sqrt(37))/4

Find the zeros of 4x^2+6x=7

The zeros of 4x^2+6x=7 are x=(-3+sqrt(37))/4 ,x=-(3+sqrt(37))/4

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4 x^{2} + 6 x = 7

x = \frac{- 3 + 37}{4}, x = - \frac{3 + 37}{4}

Decimal Notation

x = 0.77069 \dots, x = - 2.27069 \dots

Solution steps

4 x^{2} + 6 x = 7

Move

7

to the left side

4 x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 7) = 237

x_{1, 2} = \frac{- 6 \pm 2 37}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 37}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 37}{2 \cdot 4}

x = \frac{- 6 + 2 37}{2 \cdot 4} : \frac{- 3 + 37}{4}

x = \frac{- 6 - 2 37}{2 \cdot 4} : - \frac{3 + 37}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 37}{4}, x = - \frac{3 + 37}{4}

15 x^{2} + 13 x + 2

lo g_{2} (3) - lo g_{2} (12)

2 x^{2} - 10 x - 72

x^{3} - 7 x^{2} + 10 x

- \frac{10 ( - 1 ) + 2}{( 5 ( - 1 ) ^{2} + 2 ( - 1 ) ) ^{2}}

What are the solutions to the equation 4x^2+6x=7 ?
The solutions to the equation 4x^2+6x=7 are x=(-3+sqrt(37))/4 ,x=-(3+sqrt(37))/4
Find the zeros of 4x^2+6x=7
The zeros of 4x^2+6x=7 are x=(-3+sqrt(37))/4 ,x=-(3+sqrt(37))/4