What are the solutions to the equation x^2-16=-x^2+16 ?

The solutions to the equation x^2-16=-x^2+16 are x=4,x=-4

Find the zeros of x^2-16=-x^2+16

The zeros of x^2-16=-x^2+16 are x=4,x=-4

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x^{2} - 16 = - x^{2} + 16

x = 4, x = - 4

Solution steps

x^{2} - 16 = - x^{2} + 16

Move

16

to the right side

x^{2} = - x^{2} + 32

Move

x^{2}

to the left side

2 x^{2} = 32

Divide both sides by

2

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

\frac{48}{4}

\frac{( - 4 x ^{5} y ^{3} z ^{7} ) ^{3} ( - 3 x ^{2} y z ^{4} ) ^{2}}{( - 2 x ^{3} y ^{4} z ^{2} ) ^{4}}

- x^{3} + 6 x^{2}

\frac{\frac{a}{b}}{\frac{c}{d}}

\frac{1}{4} (6) + 3 (7)

What are the solutions to the equation x^2-16=-x^2+16 ?
The solutions to the equation x^2-16=-x^2+16 are x=4,x=-4
Find the zeros of x^2-16=-x^2+16
The zeros of x^2-16=-x^2+16 are x=4,x=-4