What are the solutions to the equation x^2-12x+45=0 ?

The solutions to the equation x^2-12x+45=0 are x=6+3i,x=6-3i

Find the zeros of x^2-12x+45=0

The zeros of x^2-12x+45=0 are x=6+3i,x=6-3i

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x^{2} - 12 x + 45 = 0

x = 6 + 3 i, x = 6 - 3 i

Solution steps

x^{2} - 12 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 45 : 6 i

x_{1, 2} = \frac{- ( - 12 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6 i}{2 \cdot 1} : 6 + 3 i

x = \frac{- ( - 12 ) - 6 i}{2 \cdot 1} : 6 - 3 i

The solutions to the quadratic equation are:

x = 6 + 3 i, x = 6 - 3 i

16 x^{2} - 121 y^{2}

(\frac{3}{2} + \frac{1}{2} i)^{3}

\frac{2}{1}

(n + 7)^{2} = - 2 n

a - (10 - a) = 30

What are the solutions to the equation x^2-12x+45=0 ?
The solutions to the equation x^2-12x+45=0 are x=6+3i,x=6-3i
Find the zeros of x^2-12x+45=0
The zeros of x^2-12x+45=0 are x=6+3i,x=6-3i