What are the solutions to the equation 0=x^2-4x-5 ?

The solutions to the equation 0=x^2-4x-5 are x=5,x=-1

Find the zeros of 0=x^2-4x-5

The zeros of 0=x^2-4x-5 are x=5,x=-1

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0 = x^{2} - 4 x - 5

x = 5, x = - 1

Solution steps

0 = x^{2} - 4 x - 5

Switch sides

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

- x + 10 = - 2 (x - 1)

(x + 1)^{4}

125 x^{9} - 45 x

a^{2} + 14 ab + 49 b^{2} - 4

3 (4 - 2 x) < - 5 (x - 2) + 3

What are the solutions to the equation 0=x^2-4x-5 ?
The solutions to the equation 0=x^2-4x-5 are x=5,x=-1
Find the zeros of 0=x^2-4x-5
The zeros of 0=x^2-4x-5 are x=5,x=-1