What are the solutions to the equation 3d^2-9d+6=0 ?

The solutions to the equation 3d^2-9d+6=0 are d=2,d=1

Find the zeros of 3d^2-9d+6=0

The zeros of 3d^2-9d+6=0 are d=2,d=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 d^{2} - 9 d + 6 = 0

d = 2, d = 1

Solution steps

3 d^{2} - 9 d + 6 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 \cdot 6 = 3

d_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 3}, d_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 3}

d = \frac{- ( - 9 ) + 3}{2 \cdot 3} : 2

d = \frac{- ( - 9 ) - 3}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

d = 2, d = 1

8 y - 3 = 6 y + 17

(\frac{72}{976}) = 5500

2401 - x^{4}

8 [3 a - 7] - 4 a - 2 = 62

14 + 5 x = 3 (- x + 3) - 11

What are the solutions to the equation 3d^2-9d+6=0 ?
The solutions to the equation 3d^2-9d+6=0 are d=2,d=1
Find the zeros of 3d^2-9d+6=0
The zeros of 3d^2-9d+6=0 are d=2,d=1