What are the solutions to the equation 12=2x^2+2x-12 ?

The solutions to the equation 12=2x^2+2x-12 are x=3,x=-4

Find the zeros of 12=2x^2+2x-12

The zeros of 12=2x^2+2x-12 are x=3,x=-4

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12 = 2 x^{2} + 2 x - 12

x = 3, x = - 4

Solution steps

12 = 2 x^{2} + 2 x - 12

Switch sides

2 x^{2} + 2 x - 12 = 12

Move

12

to the left side

2 x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 24) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 2}, x_{2} = \frac{- 2 - 14}{2 \cdot 2}

x = \frac{- 2 + 14}{2 \cdot 2} : 3

x = \frac{- 2 - 14}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

(\frac{1}{2} x^{4})^{7}

- 16 x^{2} - 2 x + 3

∣ x ∣ < 5

y + 6 = 0

9 x = 7 (x - 2)

What are the solutions to the equation 12=2x^2+2x-12 ?
The solutions to the equation 12=2x^2+2x-12 are x=3,x=-4
Find the zeros of 12=2x^2+2x-12
The zeros of 12=2x^2+2x-12 are x=3,x=-4