What are the solutions to the equation x^2+4x+4=16 ?

The solutions to the equation x^2+4x+4=16 are x=2,x=-6

Find the zeros of x^2+4x+4=16

The zeros of x^2+4x+4=16 are x=2,x=-6

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x^{2} + 4 x + 4 = 16

x = 2, x = - 6

Solution steps

x^{2} + 4 x + 4 = 16

Move

16

to the left side

x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 1}, x_{2} = \frac{- 4 - 8}{2 \cdot 1}

x = \frac{- 4 + 8}{2 \cdot 1} : 2

x = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

\frac{53}{43} \cdot \frac{46 n ^{2}}{31}

4 x^{2} + 20 x + 16

x - \frac{3}{5} x = 50

0.3

x^{2} + 3 x - 7 + 8 x = 4

What are the solutions to the equation x^2+4x+4=16 ?
The solutions to the equation x^2+4x+4=16 are x=2,x=-6
Find the zeros of x^2+4x+4=16
The zeros of x^2+4x+4=16 are x=2,x=-6