What is factor 2x^2-21x+40 ?

The solution to factor 2x^2-21x+40 is (2x-5)(x-8)

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factor 2x^2-21x+40

factor

2 x^{2} - 21 x + 40

(2 x - 5) (x - 8)

Solution steps

2 x^{2} - 21 x + 40

Break the expression into groups

= (2 x^{2} - 5 x) + (- 16 x + 40)

Factor out

x

from

2 x^{2} - 5 x : x (2 x - 5)

Factor out

- 8

from

- 16 x + 40 : - 8 (2 x - 5)

= x (2 x - 5) - 8 (2 x - 5)

Factor out common term

2 x - 5

= (2 x - 5) (x - 8)

x^{2} - 7 x = x - 14

\frac{4}{16}

(\frac{x}{7})^{2}

15 x^{2} - 2 x - 1 = 0

\frac{- e ^{6}}{e ^{3} - e ^{6}}