What are the solutions to the equation 3x^2-2+7x=0 ?

The solutions to the equation 3x^2-2+7x=0 are x=(-7+sqrt(73))/6 ,x=(-7-sqrt(73))/6

Find the zeros of 3x^2-2+7x=0

The zeros of 3x^2-2+7x=0 are x=(-7+sqrt(73))/6 ,x=(-7-sqrt(73))/6

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3 x^{2} - 2 + 7 x = 0

x = \frac{- 7 + 73}{6}, x = \frac{- 7 - 73}{6}

Decimal Notation

x = 0.25733 \dots, x = - 2.59066 \dots

Solution steps

3 x^{2} - 2 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 2) = 73

x_{1, 2} = \frac{- 7 \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 73}{2 \cdot 3}, x_{2} = \frac{- 7 - 73}{2 \cdot 3}

x = \frac{- 7 + 73}{2 \cdot 3} : \frac{- 7 + 73}{6}

x = \frac{- 7 - 73}{2 \cdot 3} : \frac{- 7 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 73}{6}, x = \frac{- 7 - 73}{6}

\frac{x}{3} \leq - 4

\frac{( ( x + 2 ) )}{4} - \frac{( x - 2 )}{3} x = x + \frac{( 2 ( x - 3 ) )}{3} x

\frac{3}{7} - \frac{1}{6}

x^{2} + 8 x < 7

What are the solutions to the equation 3x^2-2+7x=0 ?
The solutions to the equation 3x^2-2+7x=0 are x=(-7+sqrt(73))/6 ,x=(-7-sqrt(73))/6
Find the zeros of 3x^2-2+7x=0
The zeros of 3x^2-2+7x=0 are x=(-7+sqrt(73))/6 ,x=(-7-sqrt(73))/6