What are the solutions to the equation 4x^2+4x-3=0 ?

The solutions to the equation 4x^2+4x-3=0 are x= 1/2 ,x=-3/2

Find the zeros of 4x^2+4x-3=0

The zeros of 4x^2+4x-3=0 are x= 1/2 ,x=-3/2

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4 x^{2} + 4 x - 3 = 0

x = \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = 0.5, x = - 1.5

Solution steps

4 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 4}, x_{2} = \frac{- 4 - 8}{2 \cdot 4}

x = \frac{- 4 + 8}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 4 - 8}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{3}{2}

∣ 2 x + 8 ∣ - 1 = x

e^{- 4 t}

\frac{40}{2}

\frac{1}{9 + 4 i}

5 - \frac{1}{8} x = 4

What are the solutions to the equation 4x^2+4x-3=0 ?
The solutions to the equation 4x^2+4x-3=0 are x= 1/2 ,x=-3/2
Find the zeros of 4x^2+4x-3=0
The zeros of 4x^2+4x-3=0 are x= 1/2 ,x=-3/2