What are the solutions to the equation q^2+18q+81=0 ?

The solutions to the equation q^2+18q+81=0 are q=-9

Find the zeros of q^2+18q+81=0

The zeros of q^2+18q+81=0 are q=-9

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q^{2} + 18 q + 81 = 0

q = - 9

Solution steps

q^{2} + 18 q + 81 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

q_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

q = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

q = - 9

The solution to the quadratic equation is:

q = - 9

(x + 4) (x - 5) > 0

\frac{y ^{5}}{x ^{- 2} x ^{- 3} y ^{- 8}}

x^{4} - 3 x^{3} + 2 x^{2}

4 x - 12 > 8 x + 4

27 x^{3} + 54 x^{2} + 36 x + 8

What are the solutions to the equation q^2+18q+81=0 ?
The solutions to the equation q^2+18q+81=0 are q=-9
Find the zeros of q^2+18q+81=0
The zeros of q^2+18q+81=0 are q=-9