What are the solutions to the equation -16t^2+16t+672=0 ?

The solutions to the equation -16t^2+16t+672=0 are t=-6,t=7

Find the zeros of -16t^2+16t+672=0

The zeros of -16t^2+16t+672=0 are t=-6,t=7

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- 16 t^{2} + 16 t + 672 = 0

t = - 6, t = 7

Solution steps

- 16 t^{2} + 16 t + 672 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 672}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 672 = 208

t_{1, 2} = \frac{- 16 \pm 208}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 208}{2 ( - 16 )}, t_{2} = \frac{- 16 - 208}{2 ( - 16 )}

t = \frac{- 16 + 208}{2 ( - 16 )} : - 6

t = \frac{- 16 - 208}{2 ( - 16 )} : 7

The solutions to the quadratic equation are:

t = - 6, t = 7

\frac{8 ^{4}}{4}

32 + 18

28 x^{3} y^{3}

\frac{x}{2} = 4

∣ 5 x - 25 ∣ = 0

What are the solutions to the equation -16t^2+16t+672=0 ?
The solutions to the equation -16t^2+16t+672=0 are t=-6,t=7
Find the zeros of -16t^2+16t+672=0
The zeros of -16t^2+16t+672=0 are t=-6,t=7