What are the solutions to the equation 4x^2=10x-9 ?

The solutions to the equation 4x^2=10x-9 are x= 5/4+i(sqrt(11))/4 ,x= 5/4-i(sqrt(11))/4

Find the zeros of 4x^2=10x-9

The zeros of 4x^2=10x-9 are x= 5/4+i(sqrt(11))/4 ,x= 5/4-i(sqrt(11))/4

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4 x^{2} = 10 x - 9

x = \frac{5}{4} + i \frac{11}{4}, x = \frac{5}{4} - i \frac{11}{4}

Solution steps

4 x^{2} = 10 x - 9

Move

9

to the left side

4 x^{2} + 9 = 10 x

Move

10 x

to the left side

4 x^{2} + 9 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

(- 10)^{2} - 4 \cdot 4 \cdot 9 : 211 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 11 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 11 i}{2 \cdot 4}, x_{2} = \frac{- ( - 10 ) - 2 11 i}{2 \cdot 4}

x = \frac{- ( - 10 ) + 2 11 i}{2 \cdot 4} : \frac{5}{4} + i \frac{11}{4}

x = \frac{- ( - 10 ) - 2 11 i}{2 \cdot 4} : \frac{5}{4} - i \frac{11}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{11}{4}, x = \frac{5}{4} - i \frac{11}{4}

36 + 13 x = 5 (- 16 + 15 x) - 8

6 x - 18

6 x^{2} + 11 x + 5

\frac{n ^{4}}{( n + 1 ) ^{4}}

\frac{20}{16 i}

What are the solutions to the equation 4x^2=10x-9 ?
The solutions to the equation 4x^2=10x-9 are x= 5/4+i(sqrt(11))/4 ,x= 5/4-i(sqrt(11))/4
Find the zeros of 4x^2=10x-9
The zeros of 4x^2=10x-9 are x= 5/4+i(sqrt(11))/4 ,x= 5/4-i(sqrt(11))/4