What are the solutions to the equation u^2-13u=-36 ?

The solutions to the equation u^2-13u=-36 are u=9,u=4

Find the zeros of u^2-13u=-36

The zeros of u^2-13u=-36 are u=9,u=4

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u^{2} - 13 u = - 36

u = 9, u = 4

Solution steps

u^{2} - 13 u = - 36

Move

36

to the left side

u^{2} - 13 u + 36 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

u_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, u_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

u = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

u = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

u = 9, u = 4

3 (x - 9) = 30

3 p^{2} r^{2} + 6 p r + p

19 + 9 x - 11 = 14 - 3 x + 6

\frac{( 4 x - 1 )}{x} > 0

2 n^{2} + 17 n + 35

What are the solutions to the equation u^2-13u=-36 ?
The solutions to the equation u^2-13u=-36 are u=9,u=4
Find the zeros of u^2-13u=-36
The zeros of u^2-13u=-36 are u=9,u=4