What is (4/3+7/9)\div 5/3 ?

The solution to (4/3+7/9)\div 5/3 is 1 4/15

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(4/3+7/9)\div 5/3

(\frac{4}{3} + \frac{7}{9}) \div \frac{5}{3}

1 \frac{4}{15}

Solution steps

(\frac{4}{3} + \frac{7}{9}) \div \frac{5}{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{4}{3} + \frac{7}{9}) : \frac{19}{9}

= \frac{19}{9} \div \frac{5}{3}

Multiply and divide (left to right)

\frac{19}{9} \div \frac{5}{3} : \frac{19}{15}

= \frac{19}{15}

Convert improper fractions to mixed numbers:

\frac{19}{15} = 1 \frac{4}{15}

= 1 \frac{4}{15}

8 x + 14 = 4 x - 10

∣ 2 x + 3 ∣ = 5

419.99 \cdot x = 84.3

(4 n - 3 n^{3}) - (3 n^{3} + 4 n)

2 x^{2} + x > 12