What are the solutions to the equation n^2=-60+16n ?

The solutions to the equation n^2=-60+16n are n=10,n=6

Find the zeros of n^2=-60+16n

The zeros of n^2=-60+16n are n=10,n=6

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n^{2} = - 60 + 16 n

n = 10, n = 6

Solution steps

n^{2} = - 60 + 16 n

Move

16 n

to the left side

n^{2} - 16 n = - 60

Move

60

to the left side

n^{2} - 16 n + 60 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 60 = 4

n_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 1}, n_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 1}

n = \frac{- ( - 16 ) + 4}{2 \cdot 1} : 10

n = \frac{- ( - 16 ) - 4}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

n = 10, n = 6

- 24 \geq - 2 + \frac{2}{3 c}

6 x^{2} - 16 x + 10

\frac{1}{2} \cdot \frac{2}{5}

2 + x \geq - 1

- 2 > u^{2} + 1

What are the solutions to the equation n^2=-60+16n ?
The solutions to the equation n^2=-60+16n are n=10,n=6
Find the zeros of n^2=-60+16n
The zeros of n^2=-60+16n are n=10,n=6