What are the solutions to the equation 3x^2+20x+25=0 ?

The solutions to the equation 3x^2+20x+25=0 are x=-5/3 ,x=-5

Find the zeros of 3x^2+20x+25=0

The zeros of 3x^2+20x+25=0 are x=-5/3 ,x=-5

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3 x^{2} + 20 x + 25 = 0

x = - \frac{5}{3}, x = - 5

Decimal Notation

x = - 1.66666 \dots, x = - 5

Solution steps

3 x^{2} + 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 3 \cdot 25}{2 \cdot 3}

2 0^{2} - 4 \cdot 3 \cdot 25 = 10

x_{1, 2} = \frac{- 20 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 20 + 10}{2 \cdot 3}, x_{2} = \frac{- 20 - 10}{2 \cdot 3}

x = \frac{- 20 + 10}{2 \cdot 3} : - \frac{5}{3}

x = \frac{- 20 - 10}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - 5

2 k^{2} - 10 k

\frac{x - 14}{2} \geq \frac{x - 7}{3} + \frac{7}{6}

10 g - 5 g + g - 3 g + g = 20

25 x^{2} - 36

(x - 1) (x + 4) > 0

What are the solutions to the equation 3x^2+20x+25=0 ?
The solutions to the equation 3x^2+20x+25=0 are x=-5/3 ,x=-5
Find the zeros of 3x^2+20x+25=0
The zeros of 3x^2+20x+25=0 are x=-5/3 ,x=-5