What are the solutions to the equation -3x^2+14x-8=0 ?

The solutions to the equation -3x^2+14x-8=0 are x= 2/3 ,x=4

Find the zeros of -3x^2+14x-8=0

The zeros of -3x^2+14x-8=0 are x= 2/3 ,x=4

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- 3 x^{2} + 14 x - 8 = 0

x = \frac{2}{3}, x = 4

Decimal Notation

x = 0.66666 \dots, x = 4

Solution steps

- 3 x^{2} + 14 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 3 ) ( - 8 )}{2 ( - 3 )}

1 4^{2} - 4 (- 3) (- 8) = 10

x_{1, 2} = \frac{- 14 \pm 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 14 + 10}{2 ( - 3 )}, x_{2} = \frac{- 14 - 10}{2 ( - 3 )}

x = \frac{- 14 + 10}{2 ( - 3 )} : \frac{2}{3}

x = \frac{- 14 - 10}{2 ( - 3 )} : 4

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = 4

x^{2} \geq x + 2

\frac{4 ^{3}}{4 ^{2}}

\frac{11 ( 64 ) ^{\frac{5}{6}}}{6}

- 2 x^{2} - 3 x + 2 = 0

- x = 5

What are the solutions to the equation -3x^2+14x-8=0 ?
The solutions to the equation -3x^2+14x-8=0 are x= 2/3 ,x=4
Find the zeros of -3x^2+14x-8=0
The zeros of -3x^2+14x-8=0 are x= 2/3 ,x=4