What are the solutions to the equation 25x^2+10x+1=0 ?

The solutions to the equation 25x^2+10x+1=0 are x=-1/5

Find the zeros of 25x^2+10x+1=0

The zeros of 25x^2+10x+1=0 are x=-1/5

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25 x^{2} + 10 x + 1 = 0

x = - \frac{1}{5}

Decimal Notation

x = - 0.2

Solution steps

25 x^{2} + 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

1 0^{2} - 4 \cdot 25 \cdot 1 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 25}

x = \frac{- 10}{2 \cdot 25}

\frac{- 10}{2 \cdot 25} = - \frac{1}{5}

x = - \frac{1}{5}

The solution to the quadratic equation is:

x = - \frac{1}{5}

16 \div 4 (4)

b^{2} + 49 - (b - 7)^{2}

\frac{v}{32} > - 2

2 x - 2 x = 35

6 x^{2} + 10 x + 4

What are the solutions to the equation 25x^2+10x+1=0 ?
The solutions to the equation 25x^2+10x+1=0 are x=-1/5
Find the zeros of 25x^2+10x+1=0
The zeros of 25x^2+10x+1=0 are x=-1/5