What is (4x+2)/6 <(2x+1)/3 ?

The solution to (4x+2)/6 <(2x+1)/3 is No Solution

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(4x+2)/6 <(2x+1)/3

\frac{4 x + 2}{6} < \frac{2 x + 1}{3}

No Solution

Solution steps

\frac{4 x + 2}{6} < \frac{2 x + 1}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(4 x + 2) \cdot 3 < 6 (2 x + 1)

Expand

(4 x + 2) \cdot 3 : 12 x + 6

Expand

6 (2 x + 1) : 12 x + 6

12 x + 6 < 12 x + 6

Move

6

to the right side

12 x < 12 x

Move

12 x

to the left side

0 < 0

Therefore, the solution is

No Solution

\frac{8}{3} - (\frac{7}{3} - \frac{4}{3}) + \frac{12}{3}

(6 x^{6} + 6 x) (x + 3) (x - 6)

(x + 5)^{2} = - 81

2 (- 2 x + 2) - 3 x + 3 = 0

- x^{3} + 6 x^{2} - 32