What are the solutions to the equation 18x^2+18x=0 ?

The solutions to the equation 18x^2+18x=0 are x=0,x=-1

Find the zeros of 18x^2+18x=0

The zeros of 18x^2+18x=0 are x=0,x=-1

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18 x^{2} + 18 x = 0

x = 0, x = - 1

Solution steps

18 x^{2} + 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 18 \cdot 0}{2 \cdot 18}

1 8^{2} - 4 \cdot 18 \cdot 0 = 18

x_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 18 + 18}{2 \cdot 18}, x_{2} = \frac{- 18 - 18}{2 \cdot 18}

x = \frac{- 18 + 18}{2 \cdot 18} : 0

x = \frac{- 18 - 18}{2 \cdot 18} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

\frac{x}{11} = \frac{x}{12} - 14

- 84 = - 4 (6 x - 3)

5 (3 x + 2) = 4 x - 7

lo g_{5} (∣ 1 - x ∣) = 1

(\frac{w ^{4}}{9 x ^{- 2}})^{- \frac{1}{2}}

What are the solutions to the equation 18x^2+18x=0 ?
The solutions to the equation 18x^2+18x=0 are x=0,x=-1
Find the zeros of 18x^2+18x=0
The zeros of 18x^2+18x=0 are x=0,x=-1