What are the solutions to the equation 3x^2+7x-1=0 ?

The solutions to the equation 3x^2+7x-1=0 are x=(-7+sqrt(61))/6 ,x=(-7-sqrt(61))/6

Find the zeros of 3x^2+7x-1=0

The zeros of 3x^2+7x-1=0 are x=(-7+sqrt(61))/6 ,x=(-7-sqrt(61))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 7 x - 1 = 0

x = \frac{- 7 + 61}{6}, x = \frac{- 7 - 61}{6}

Decimal Notation

x = 0.13504 \dots, x = - 2.46837 \dots

Solution steps

3 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 1) = 61

x_{1, 2} = \frac{- 7 \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 61}{2 \cdot 3}, x_{2} = \frac{- 7 - 61}{2 \cdot 3}

x = \frac{- 7 + 61}{2 \cdot 3} : \frac{- 7 + 61}{6}

x = \frac{- 7 - 61}{2 \cdot 3} : \frac{- 7 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 61}{6}, x = \frac{- 7 - 61}{6}

p^{2} + 6 p + 8 = 0

d^{2} + 7 d + 10 = 0

2 x^{3} - 5 x^{2} - 3 x \geq 0

\frac{2 - 3 x}{3} = \frac{4 x - 6}{2} + 5

(x + 1)^{2} = 2

What are the solutions to the equation 3x^2+7x-1=0 ?
The solutions to the equation 3x^2+7x-1=0 are x=(-7+sqrt(61))/6 ,x=(-7-sqrt(61))/6
Find the zeros of 3x^2+7x-1=0
The zeros of 3x^2+7x-1=0 are x=(-7+sqrt(61))/6 ,x=(-7-sqrt(61))/6