What are the solutions to the equation (4y+8)^2=64 ?

The solutions to the equation (4y+8)^2=64 are y=0,y=-4

Find the zeros of (4y+8)^2=64

The zeros of (4y+8)^2=64 are y=0,y=-4

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(4 y + 8)^{2} = 64

y = 0, y = - 4

Solution steps

(4 y + 8)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 y + 8 = 64 : y = 0

Solve

4 y + 8 = - 64 : y = - 4

The solutions to the quadratic equation are:

y = 0, y = - 4

x^{2} + 7 x + 12 = 0

\frac{2}{3} (6 - 9 x) = 16

8 x^{3} - 64 x^{2} + x - 8

\frac{d y}{d t} - y = - \frac{t}{y}

\frac{( 9 s t ) ^{\frac{3}{2}}}{( 27 s ^{3} t ^{- 4} ) ^{\frac{2}{3}}}

What are the solutions to the equation (4y+8)^2=64 ?
The solutions to the equation (4y+8)^2=64 are y=0,y=-4
Find the zeros of (4y+8)^2=64
The zeros of (4y+8)^2=64 are y=0,y=-4