What are the solutions to the equation 4x^2-5x-9=0 ?

The solutions to the equation 4x^2-5x-9=0 are x= 9/4 ,x=-1

Find the zeros of 4x^2-5x-9=0

The zeros of 4x^2-5x-9=0 are x= 9/4 ,x=-1

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4 x^{2} - 5 x - 9 = 0

x = \frac{9}{4}, x = - 1

Decimal Notation

x = 2.25, x = - 1

Solution steps

4 x^{2} - 5 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 9) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 4}

x = \frac{- ( - 5 ) + 13}{2 \cdot 4} : \frac{9}{4}

x = \frac{- ( - 5 ) - 13}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = - 1

240 = 6 x^{2} + 4 x

lo g_{16} (\frac{1}{64})

5 + x - 12 = 2 x - 7

\frac{1 0 ^{\frac{1}{3}} \cdot 3 ^{\frac{1}{3}}}{5 ^{\frac{1}{3}}}

x^{2} + x - 6 \leq 0

What are the solutions to the equation 4x^2-5x-9=0 ?
The solutions to the equation 4x^2-5x-9=0 are x= 9/4 ,x=-1
Find the zeros of 4x^2-5x-9=0
The zeros of 4x^2-5x-9=0 are x= 9/4 ,x=-1