What are the solutions to the equation 1.5x^2-4.2x+2.7=0 ?

The solutions to the equation 1.5x^2-4.2x+2.7=0 are x= 9/5 ,x=1

Find the zeros of 1.5x^2-4.2x+2.7=0

The zeros of 1.5x^2-4.2x+2.7=0 are x= 9/5 ,x=1

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1.5 x^{2} - 4.2 x + 2.7 = 0

x = \frac{9}{5}, x = 1

Decimal Notation

x = 1.8, x = 1

Solution steps

1.5 x^{2} - 4.2 x + 2.7 = 0

Multiply both sides by

10

15 x^{2} - 42 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 15 \cdot 27}{2 \cdot 15}

(- 42)^{2} - 4 \cdot 15 \cdot 27 = 12

x_{1, 2} = \frac{- ( - 42 ) \pm 12}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 12}{2 \cdot 15}, x_{2} = \frac{- ( - 42 ) - 12}{2 \cdot 15}

x = \frac{- ( - 42 ) + 12}{2 \cdot 15} : \frac{9}{5}

x = \frac{- ( - 42 ) - 12}{2 \cdot 15} : 1

The solutions to the quadratic equation are:

x = \frac{9}{5}, x = 1

(13 + 6)^{2}

\frac{3}{4} + \frac{5}{8} - \frac{7}{12}

(- 7 + 7 i) (- 10 - 9 i)

\frac{6}{15} = 2 - \frac{x}{5}

\frac{4}{7} x - 4 > 8

What are the solutions to the equation 1.5x^2-4.2x+2.7=0 ?
The solutions to the equation 1.5x^2-4.2x+2.7=0 are x= 9/5 ,x=1
Find the zeros of 1.5x^2-4.2x+2.7=0
The zeros of 1.5x^2-4.2x+2.7=0 are x= 9/5 ,x=1