What are the solutions to the equation 9^2+b^2=41^2 ?

The solutions to the equation 9^2+b^2=41^2 are b=40,b=-40

Find the zeros of 9^2+b^2=41^2

The zeros of 9^2+b^2=41^2 are b=40,b=-40

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9^{2} + b^{2} = 4 1^{2}

b = 40, b = - 40

Solution steps

9^{2} + b^{2} = 4 1^{2}

Move

9^{2}

to the right side

b^{2} = 1600

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 1600, b = - 1600

1600 = 40

- 1600 = - 40

b = 40, b = - 40

2 lo g_{3} (\frac{1}{52})

- \frac{\frac{5}{9}}{( - \frac{11}{6} )}

- 3 x = 21

- 12 \cdot 6

3 x^{2} + 4 x - 10 = 0

What are the solutions to the equation 9^2+b^2=41^2 ?
The solutions to the equation 9^2+b^2=41^2 are b=40,b=-40
Find the zeros of 9^2+b^2=41^2
The zeros of 9^2+b^2=41^2 are b=40,b=-40