What are the solutions to the equation 4x^2-3x+2=0 ?

The solutions to the equation 4x^2-3x+2=0 are x= 3/8+i(sqrt(23))/8 ,x= 3/8-i(sqrt(23))/8

Find the zeros of 4x^2-3x+2=0

The zeros of 4x^2-3x+2=0 are x= 3/8+i(sqrt(23))/8 ,x= 3/8-i(sqrt(23))/8

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4 x^{2} - 3 x + 2 = 0

x = \frac{3}{8} + i \frac{23}{8}, x = \frac{3}{8} - i \frac{23}{8}

Solution steps

4 x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

Simplify

(- 3)^{2} - 4 \cdot 4 \cdot 2 : 23 i

x_{1, 2} = \frac{- ( - 3 ) \pm 23 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 23 i}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 23 i}{2 \cdot 4}

x = \frac{- ( - 3 ) + 23 i}{2 \cdot 4} : \frac{3}{8} + i \frac{23}{8}

x = \frac{- ( - 3 ) - 23 i}{2 \cdot 4} : \frac{3}{8} - i \frac{23}{8}

The solutions to the quadratic equation are:

x = \frac{3}{8} + i \frac{23}{8}, x = \frac{3}{8} - i \frac{23}{8}

y^{2} + y - 6

\frac{0}{π}

\frac{x}{8} - 2 = - 3

35 + 20 - 45

What are the solutions to the equation 4x^2-3x+2=0 ?
The solutions to the equation 4x^2-3x+2=0 are x= 3/8+i(sqrt(23))/8 ,x= 3/8-i(sqrt(23))/8
Find the zeros of 4x^2-3x+2=0
The zeros of 4x^2-3x+2=0 are x= 3/8+i(sqrt(23))/8 ,x= 3/8-i(sqrt(23))/8