What are the solutions to the equation 3x^2+2x-3=0 ?

The solutions to the equation 3x^2+2x-3=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3

Find the zeros of 3x^2+2x-3=0

The zeros of 3x^2+2x-3=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3

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3 x^{2} + 2 x - 3 = 0

x = \frac{- 1 + 10}{3}, x = - \frac{1 + 10}{3}

Decimal Notation

x = 0.72075 \dots, x = - 1.38742 \dots

Solution steps

3 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 3) = 210

x_{1, 2} = \frac{- 2 \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 10}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 10}{2 \cdot 3}

x = \frac{- 2 + 2 10}{2 \cdot 3} : \frac{- 1 + 10}{3}

x = \frac{- 2 - 2 10}{2 \cdot 3} : - \frac{1 + 10}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 10}{3}, x = - \frac{1 + 10}{3}

\frac{f}{3} - 1 = 1

\frac{100 !}{97 ! 3 !}

2 x - 3 x^{2} = 0

- \frac{2}{( \frac{1}{9} ) ^{\frac{3}{2}}}

8 - 4

What are the solutions to the equation 3x^2+2x-3=0 ?
The solutions to the equation 3x^2+2x-3=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3
Find the zeros of 3x^2+2x-3=0
The zeros of 3x^2+2x-3=0 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3