What are the solutions to the equation 25x^2+10x-6=0 ?

The solutions to the equation 25x^2+10x-6=0 are x=(-1+sqrt(7))/5 ,x=-(1+sqrt(7))/5

Find the zeros of 25x^2+10x-6=0

The zeros of 25x^2+10x-6=0 are x=(-1+sqrt(7))/5 ,x=-(1+sqrt(7))/5

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25 x^{2} + 10 x - 6 = 0

x = \frac{- 1 + 7}{5}, x = - \frac{1 + 7}{5}

Decimal Notation

x = 0.32915 \dots, x = - 0.72915 \dots

Solution steps

25 x^{2} + 10 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 ( - 6 )}{2 \cdot 25}

1 0^{2} - 4 \cdot 25 (- 6) = 107

x_{1, 2} = \frac{- 10 \pm 10 7}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 10 + 10 7}{2 \cdot 25}, x_{2} = \frac{- 10 - 10 7}{2 \cdot 25}

x = \frac{- 10 + 10 7}{2 \cdot 25} : \frac{- 1 + 7}{5}

x = \frac{- 10 - 10 7}{2 \cdot 25} : - \frac{1 + 7}{5}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{5}, x = - \frac{1 + 7}{5}

(- 4)^{2}

8 m^{2} - 5 m - 3

7 - ∣ 2 x + 6 ∣ \leq 5

- 3 x^{2} + 10 x - 8

x^{2} + \frac{5}{2} x - \frac{3}{2}

What are the solutions to the equation 25x^2+10x-6=0 ?
The solutions to the equation 25x^2+10x-6=0 are x=(-1+sqrt(7))/5 ,x=-(1+sqrt(7))/5
Find the zeros of 25x^2+10x-6=0
The zeros of 25x^2+10x-6=0 are x=(-1+sqrt(7))/5 ,x=-(1+sqrt(7))/5