What are the solutions to the equation 0.9x^2-8x+70=0 ?

The solutions to the equation 0.9x^2-8x+70=0 are x= 40/9+i(10sqrt(47))/9 ,x= 40/9-i(10sqrt(47))/9

Find the zeros of 0.9x^2-8x+70=0

The zeros of 0.9x^2-8x+70=0 are x= 40/9+i(10sqrt(47))/9 ,x= 40/9-i(10sqrt(47))/9

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0.9 x^{2} - 8 x + 70 = 0

x = \frac{40}{9} + i \frac{10 47}{9}, x = \frac{40}{9} - i \frac{10 47}{9}

Solution steps

0.9 x^{2} - 8 x + 70 = 0

Multiply both sides by

10

9 x^{2} - 80 x + 700 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 9 \cdot 700}{2 \cdot 9}

Simplify

(- 80)^{2} - 4 \cdot 9 \cdot 700 : 2047 i

x_{1, 2} = \frac{- ( - 80 ) \pm 20 47 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 20 47 i}{2 \cdot 9}, x_{2} = \frac{- ( - 80 ) - 20 47 i}{2 \cdot 9}

x = \frac{- ( - 80 ) + 20 47 i}{2 \cdot 9} : \frac{40}{9} + i \frac{10 47}{9}

x = \frac{- ( - 80 ) - 20 47 i}{2 \cdot 9} : \frac{40}{9} - i \frac{10 47}{9}

The solutions to the quadratic equation are:

x = \frac{40}{9} + i \frac{10 47}{9}, x = \frac{40}{9} - i \frac{10 47}{9}

\frac{4}{5} \cdot \frac{1}{4}

11 - 7

8 x + 7 < 6 x + 9

3 p^{2} - 3 p - 36

\frac{1}{3} (x + \frac{6}{5}) = - \frac{8}{5}

What are the solutions to the equation 0.9x^2-8x+70=0 ?
The solutions to the equation 0.9x^2-8x+70=0 are x= 40/9+i(10sqrt(47))/9 ,x= 40/9-i(10sqrt(47))/9
Find the zeros of 0.9x^2-8x+70=0
The zeros of 0.9x^2-8x+70=0 are x= 40/9+i(10sqrt(47))/9 ,x= 40/9-i(10sqrt(47))/9