What is factor x^4-5x^2+10x-6 ?

The solution to factor x^4-5x^2+10x-6 is (x-1)(x+3)(x^2-2x+2)

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factor x^4-5x^2+10x-6

factor

x^{4} - 5 x^{2} + 10 x - 6

(x - 1) (x + 3) (x^{2} - 2 x + 2)

Solution steps

x^{4} - 5 x^{2} + 10 x - 6

Use the rational root theorem

= (x - 1) \frac{x ^{4} - 5 x ^{2} + 10 x - 6}{x - 1}

\frac{x ^{4} - 5 x ^{2} + 10 x - 6}{x - 1} = x^{3} + x^{2} - 4 x + 6

= (x - 1) (x^{3} + x^{2} - 4 x + 6)

Factor

x^{3} + x^{2} - 4 x + 6 : (x + 3) (x^{2} - 2 x + 2)

= (x - 1) (x + 3) (x^{2} - 2 x + 2)

7 (1 + 5 n) + 6 (1 + 4 n) = 13

7 (x + 9) = 5 (x - 2)

7^{- \frac{1}{2}}

x^{5} y^{5} (- 10 x y^{5})

(2 + 9 i)^{2}

What is factor x^4-5x^2+10x-6 ?
The solution to factor x^4-5x^2+10x-6 is (x-1)(x+3)(x^2-2x+2)