What are the solutions to the equation 16z^2-56z+49=25 ?

The solutions to the equation 16z^2-56z+49=25 are z=3,z= 1/2

Find the zeros of 16z^2-56z+49=25

The zeros of 16z^2-56z+49=25 are z=3,z= 1/2

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16 z^{2} - 56 z + 49 = 25

z = 3, z = \frac{1}{2}

Decimal Notation

z = 3, z = 0.5

Solution steps

16 z^{2} - 56 z + 49 = 25

Move

25

to the left side

16 z^{2} - 56 z + 24 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 16 \cdot 24}{2 \cdot 16}

(- 56)^{2} - 4 \cdot 16 \cdot 24 = 40

z_{1, 2} = \frac{- ( - 56 ) \pm 40}{2 \cdot 16}

Separate the solutions

z_{1} = \frac{- ( - 56 ) + 40}{2 \cdot 16}, z_{2} = \frac{- ( - 56 ) - 40}{2 \cdot 16}

z = \frac{- ( - 56 ) + 40}{2 \cdot 16} : 3

z = \frac{- ( - 56 ) - 40}{2 \cdot 16} : \frac{1}{2}

The solutions to the quadratic equation are:

z = 3, z = \frac{1}{2}

\frac{45}{4}

4 ∣ x + 9 ∣ - 8 \geq 4

- (\frac{9 i}{2} + \frac{3}{14}) + (\frac{- 5 i}{7} - 3)

\frac{3}{4} x^{2} - 3 = - \frac{3}{4} x^{2} + 3

5 < \frac{1}{2} p + 3 < 8

What are the solutions to the equation 16z^2-56z+49=25 ?
The solutions to the equation 16z^2-56z+49=25 are z=3,z= 1/2
Find the zeros of 16z^2-56z+49=25
The zeros of 16z^2-56z+49=25 are z=3,z= 1/2