What are the solutions to the equation 9x^2+18x+8=0 ?

The solutions to the equation 9x^2+18x+8=0 are x=-2/3 ,x=-4/3

Find the zeros of 9x^2+18x+8=0

The zeros of 9x^2+18x+8=0 are x=-2/3 ,x=-4/3

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9 x^{2} + 18 x + 8 = 0

x = - \frac{2}{3}, x = - \frac{4}{3}

Decimal Notation

x = - 0.66666 \dots, x = - 1.33333 \dots

Solution steps

9 x^{2} + 18 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 8}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 \cdot 8 = 6

x_{1, 2} = \frac{- 18 \pm 6}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 6}{2 \cdot 9}, x_{2} = \frac{- 18 - 6}{2 \cdot 9}

x = \frac{- 18 + 6}{2 \cdot 9} : - \frac{2}{3}

x = \frac{- 18 - 6}{2 \cdot 9} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - \frac{4}{3}

x^{4} - x^{3} - 28 x^{2} + 76 x - 48

\frac{5}{12} - \frac{1}{6}

∣ 3 x - 7 ∣ \geq 2

5 x \geq 7 x + 4

(3.775)^{\frac{3}{2}}

What are the solutions to the equation 9x^2+18x+8=0 ?
The solutions to the equation 9x^2+18x+8=0 are x=-2/3 ,x=-4/3
Find the zeros of 9x^2+18x+8=0
The zeros of 9x^2+18x+8=0 are x=-2/3 ,x=-4/3