What is (12x^3y^{-2})^{2/3} ?

The solution to (12x^3y^{-2})^{2/3} is (12^{2/3}x^2)/(y^{4/3)}

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simplify (12x^3y^{-2})^{2/3}

simplify

(12 x^{3} y^{- 2})^{\frac{2}{3}}

\frac{1 2 ^{\frac{2}{3}} x ^{2}}{y ^{\frac{4}{3}}}

Solution steps

(12 x^{3} y^{- 2})^{\frac{2}{3}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(12 x^{3} y^{- 2})^{\frac{2}{3}} = 1 2^{\frac{2}{3}} (x^{3})^{\frac{2}{3}} (y^{- 2})^{\frac{2}{3}}

= 1 2^{\frac{2}{3}} (x^{3})^{\frac{2}{3}} (y^{- 2})^{\frac{2}{3}}

Simplify

(x^{3})^{\frac{2}{3}} : x^{2}

= 1 2^{\frac{2}{3}} x^{2} (y^{- 2})^{\frac{2}{3}}

Simplify

(y^{- 2})^{\frac{2}{3}} : \frac{1}{y ^{\frac{4}{3}}}

= 1 2^{\frac{2}{3}} x^{2} \frac{1}{y ^{\frac{4}{3}}}

Simplify

1 2^{\frac{2}{3}} x^{2} \frac{1}{y ^{\frac{4}{3}}} : \frac{1 2 ^{\frac{2}{3}} x ^{2}}{y ^{\frac{4}{3}}}

= \frac{1 2 ^{\frac{2}{3}} x ^{2}}{y ^{\frac{4}{3}}}

2 x^{2} + 7 x - 30

x^{2} \cdot x^{\frac{1}{2}}

∣ 6 x - 5 ∣ > 0

12 x = 9 x - 4

2 x (x + 1)^{3} + 3 (x + 1)^{2} x^{2}

What is (12x^3y^{-2})^{2/3} ?
The solution to (12x^3y^{-2})^{2/3} is (12^{2/3}x^2)/(y^{4/3)}