What are the solutions to the equation 2x^2-16x=-30 ?

The solutions to the equation 2x^2-16x=-30 are x=5,x=3

Find the zeros of 2x^2-16x=-30

The zeros of 2x^2-16x=-30 are x=5,x=3

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2 x^{2} - 16 x = - 30

x = 5, x = 3

Solution steps

2 x^{2} - 16 x = - 30

Move

30

to the left side

2 x^{2} - 16 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 30}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 30 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 2}

x = \frac{- ( - 16 ) + 4}{2 \cdot 2} : 5

x = \frac{- ( - 16 ) - 4}{2 \cdot 2} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

\frac{\frac{1}{12}}{\frac{1}{6}}

2 x^{2} - 12 x + 11 = 0

n^{2} + 18 n + 5200 = 0

(5 x + 3)^{2} = 16

- 1 < 2 x - 1 \leq 7

What are the solutions to the equation 2x^2-16x=-30 ?
The solutions to the equation 2x^2-16x=-30 are x=5,x=3
Find the zeros of 2x^2-16x=-30
The zeros of 2x^2-16x=-30 are x=5,x=3