What is the answer to x^2-3x=(x+4)(x-5) ?

The answer to x^2-3x=(x+4)(x-5) is x=10

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x^2-3x=(x+4)(x-5)

x^{2} - 3 x = (x + 4) (x - 5)

x = 10

Solution steps

x^{2} - 3 x = (x + 4) (x - 5)

Expand

(x + 4) (x - 5) : x^{2} - x - 20

x^{2} - 3 x = x^{2} - x - 20

Subtract

x^{2} - x

from both sides

x^{2} - 3 x - (x^{2} - x) = x^{2} - x - 20 - (x^{2} - x)

Simplify

- 2 x = - 20

Divide both sides by

- 2

x = 10

7 x + 40 = 3 x + 112

- \frac{5}{3} x + \frac{2}{5} - \frac{1}{3} x + 1 = 0

a^{2} - 6 a + 5

9 x^{7} + 6 x^{5}

\frac{13}{17} = \frac{x}{11}

What is the answer to x^2-3x=(x+4)(x-5) ?
The answer to x^2-3x=(x+4)(x-5) is x=10
Solve for x: x^2-3x=(x+4)(x-5)
The solution is x=10