What are the solutions to the equation 15^2+b^2=17^2 ?

The solutions to the equation 15^2+b^2=17^2 are b=8,b=-8

Find the zeros of 15^2+b^2=17^2

The zeros of 15^2+b^2=17^2 are b=8,b=-8

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1 5^{2} + b^{2} = 1 7^{2}

b = 8, b = - 8

Solution steps

1 5^{2} + b^{2} = 1 7^{2}

Move

1 5^{2}

to the right side

b^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 64, b = - 64

64 = 8

- 64 = - 8

b = 8, b = - 8

x^{2} - 7 x - 78 = 0

3 (4 b - 3) \leq 4 (b + 1) - 5 b

m^{2} + m - 6

4 \frac{405 x ^{3} y ^{3}}{5 x ^{- 1} y}

3 (x) + (14 - x) = 2 \cdot x (2 x - 21)

What are the solutions to the equation 15^2+b^2=17^2 ?
The solutions to the equation 15^2+b^2=17^2 are b=8,b=-8
Find the zeros of 15^2+b^2=17^2
The zeros of 15^2+b^2=17^2 are b=8,b=-8